-3x^2+210x=2703

Solution for -3x^2+210x=2703 equation:

-3x^2+210x=2703

We move all terms to the left:

-3x^2+210x-(2703)=0

a = -3; b = 210; c = -2703;
Δ = b2-4ac
Δ = 2102-4·(-3)·(-2703)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11664}=108$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-108}{2*-3}=\frac{-318}{-6}
=+53
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+108}{2*-3}=\frac{-102}{-6}
=+17
$